Class 12 Maths, Worked in Full Past papersGet updates
CBSE Sample Paper 2025-26 · Section A · 1 mark

Q2: Orders m,n,p,qm, n, p, q when ABAB and ACAC are square

Sample 2025-26Ch 3 · Matrices
The question

If for three matrices A=[aij]m×4A = [a_{ij}]_{m \times 4}⁠, B=[bij]n×3B = [b_{ij}]_{n \times 3} and C=[cij]p×qC = [c_{ij}]_{p \times q} products ABAB and ACAC both are defined and are square matrices of same order, then value of m,n,pm, n, p and qq are:

(A) m=q=3m = q = 3 and n=p=4n = p = 4

(B) m=2,q=3m = 2, q = 3 and n=p=4n = p = 4

(C) m=q=4m = q = 4 and n=p=3n = p = 3

(D) m=4,p=2m = 4, p = 2 and n=q=3n = q = 3

Exam answer

ABAB is defined, so n=4n = 4⁠, and ABAB is of order m×3m \times 3⁠.

Why?

A product PQPQ is defined only when the number of columns of PP equals the number of rows of QQ⁠. AA has 4 columns and BB has nn rows, so n=4n = 4⁠.

The product takes its rows from the first matrix and its columns from the second:

(m×4)(4×3)→m×3(m \times 4)(4 \times 3) \to m \times 3

ACAC is defined, so p=4p = 4⁠, and ACAC is of order m×qm \times q⁠.

Why?

The same rule: AA has 4 columns and CC has pp rows, so p=4p = 4⁠.

(m×4)(4×q)→m×q(m \times 4)(4 \times q) \to m \times q

ABAB is square, so m=3m = 3⁠. ACAC is of the same order, so m×q=3×3m \times q = 3 \times 3 and q=3q = 3⁠.

Why?

A square matrix has as many rows as columns. ABAB has 3 columns, so it needs 3 rows: m=3m = 3⁠.

Same order means the same number of rows and the same number of columns. So ACAC is also 3×33 \times 3⁠, which gives q=3q = 3⁠.

So m=q=3m = q = 3 and n=p=4n = p = 4⁠. Option (B) has m=2m = 2⁠, and options (C) and (D) have n=3n = 3⁠, so they fail.

Answer: (A) m=q=3m = q = 3 and n=p=4n = p = 4

Where this comes from

Chapter 3, Matrices: Order of a product of matrices.

Question type: One-mark MCQs

How to spot it: click to see

Type 6. One-mark MCQs: orders and definitions

Spot it: four options, asking when a sum or product is defined, what order it has, or what a word such as symmetric or inverse means.

Here: Write the orders: ABAB is (m×4)(n×3)(m \times 4)(n \times 3)⁠, so n=4n = 4⁠, and ACAC needs p=4p = 4⁠. ABAB is m×3m \times 3 and square, so m=3m = 3⁠; ACAC is m×qm \times q of the same order, so q=3q = 3⁠.

Found an error?

Tell us if something on this page is wrong or unclear. Send feedback on this question →