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CBSE Sample Paper 2024-25 · Section A · 1 mark

Q2: Restrictions on n,k,pn, k, p so that PY+WYPY + WY is defined

Sample 2024-25Ch 3 · Matrices
The question

Assume X,Y,Z,WX, Y, Z, W and PP are matrices of order 2×n2 \times n⁠, 3×k3 \times k⁠, 2×p2 \times p⁠, n×3n \times 3 and p×kp \times k⁠, respectively. Then the restriction on n,kn, k and pp so that PY+WYPY + WY will be defined are:

(A) k=3,p=nk = 3, p = n

(B) kk is arbitrary, p=2p = 2

(C) pp is arbitrary, k=3k = 3

(D) k=2,p=3k = 2, p = 3

Exam answer

Pp×k Y3×kP_{p \times k}\,Y_{3 \times k} is defined only if k=3k = 3⁠. Then PYPY is of order p×kp \times k⁠.

Why?

A product XYXY is defined only when the number of columns of XX equals the number of rows of YY⁠. The answer then has the rows of XX and the columns of YY⁠:

Xm×n Yn×r=(XY)m×rX_{m \times n}\,Y_{n \times r} = (XY)_{m \times r}

PP has kk columns and YY has 3 rows, so we need k=3k = 3⁠.

Wn×3 Y3×kW_{n \times 3}\,Y_{3 \times k} is defined and is of order n×kn \times k⁠.

Why?

WW has 3 columns and YY has 3 rows, so WYWY is always defined. It takes its nn rows from WW and its kk columns from YY⁠.

PY+WYPY + WY is defined only if both have the same order: p×k=n×kp \times k = n \times k⁠, so p=np = n⁠.

Why?

Two matrices can be added only when they have the same order. The columns already match (kk and kk⁠), so the rows must match: p=np = n⁠.

Option (C) misses p=np = n⁠, option (B) fixes p=2p = 2 instead, and in option (D) k=2k = 2 makes PYPY undefined.

∴ k=3\therefore\ k = 3 and p=np = n⁠.

Answer: (A) k=3,p=nk = 3, p = n

Where this comes from

Chapter 3, Matrices: Order of matrices: when PY + WY is defined.

Question type: One-mark MCQs

How to spot it: click to see

Type 6. One-mark MCQs: orders and definitions

Spot it: four options, asking when a sum or product is defined, what order it has, or what a word such as symmetric or inverse means.

Here: Write the orders: PP is p×kp \times k and YY is 3×k3 \times k⁠, so PYPY needs k=3k = 3⁠. PYPY is p×kp \times k and WYWY is n×kn \times k⁠, so the sum needs p=np = n⁠.

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