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CBSE Sample Paper 2021-22 (Term 2) · Section A · 2 marks

Q2: Sum of the order and degree of ddx(dydx)=5\frac{d}{dx}\left(\frac{dy}{dx}\right) = 5

The question

Write the sum of the order and the degree of the following differential equation:

ddx(dydx)=5\frac{d}{dx}\left(\frac{dy}{dx}\right) = 5
Exam answer

The given differential equation is

d2ydx2=5\frac{d^2y}{dx^2} = 5
Why?

ddx(dydx)\frac{d}{dx}\left(\frac{dy}{dx}\right) means: differentiate dydx\frac{dy}{dx} once more. That is the second derivative, written d2ydx2\frac{d^2y}{dx^2}⁠.

Always rewrite the equation in this simple form before reading off the order and the degree.

The highest order derivative present is d2ydx2\frac{d^2y}{dx^2}⁠, so order = 2.

Why?

The order of a differential equation is the order of the highest derivative in it. A second derivative gives order 2.

The equation is a polynomial in the derivatives and the highest power of d2ydx2\frac{d^2y}{dx^2} is 1, so degree = 1.

Why?

The degree is defined only when the equation is a polynomial in the derivatives: no derivative under a root, in a denominator, or inside a function such as sin. The degree is then the highest power of the highest order derivative.

Here d2ydx2\frac{d^2y}{dx^2} appears to the power 1.

Watch out: the 2 in d2ydx2\frac{d^2y}{dx^2} shows the order, not a power.

∴\therefore Sum of order and degree =2+1=3= 2 + 1 = 3⁠.

Where this comes from

Chapter 9, Differential Equations: Order and degree of a differential equation.

Question type: Order and degree

How to spot it: click to see

Type 1. Order and degree: the highest derivative, and its power

Spot it: "find the order and degree (if defined)". Often an MCQ.

Here: Write ddx(dydx)\frac{d}{dx}\left(\frac{dy}{dx}\right) as d2ydx2\frac{d^2y}{dx^2}⁠. It is the highest derivative, to power 1: order 2, degree 1, sum 3.

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