Example 6: The identity function is continuous everywhere
Prove that the identity function on real numbers given by is continuous at every real number.
Let be any real number. Then .
Since , is continuous at .
As is arbitrary, is continuous at every real number. Hence proved.
Want the reason behind every step, the basics and the checks?
The identity function returns its input unchanged, so the distance between and is exactly the distance between and . Bringing close to therefore brings equally close to , at every point . The proof is this observation, carried out at an arbitrary point.
- Given
- for every real .
- To prove
- is continuous at every real number.
- Plan
- Take an arbitrary real . Find , the left-hand limit and the right-hand limit at , and show they are equal (Definition 1).
Basics you need
sends every number to itself: , . Its graph is the line through the origin at 45°. Basics: functions
means can be made as close to as we like by taking close enough to , . Basics: what a limit is
uses only , and only . The limit exists when both exist and agree. Basics: left-hand and right-hand limits
For in the domain, is continuous at iff the left-hand limit, the right-hand limit and exist and are equal. Lesson: continuity at a point
Solution
Fix an arbitrary point and find
is defined for every real , so the domain is . Let be any real number. Then
"Continuous at every real number" is a "for every" statement, so we argue at a point about which nothing is assumed beyond being real. Continuity at is only meaningful because is in the domain.The identity function's output equals its input. Basics: functionsMeasure how far is from
For every real ,
So if is within 0.01 of , then is within 0.01 of ; if is within 0.000001 of , so is . Any demanded closeness is met by taking just as close to , from either side.
This is the meaning of a limit (Basic 2) applied directly. It is also the honest reason behind the textbook's line : that line is not a calculation but a direct consequence of .The two one-sided limits
Step 2 holds for and for , so
For example, with :
side of 3 left left right right The rule is the same on both sides of , so both one-sided limits come out the same way. Since they agree, .Compare and conclude
All three agree, so and is continuous at . Because was arbitrary, the identity function is continuous at every real number.
Definition 1 is satisfied at the arbitrary point , which proves it at every real number. So is a continuous function (Definition 2).
For every real , . Hence the identity function is continuous at every real number, as the textbook proves.
At : and , each from , exactly the distance of from .
- Proving it at one point only. "Continuous at every real number" needs an arbitrary , not or .
- Treating as obvious without reason. It is true because ; that is worth saying once.
- Mixing up and . is the fixed point being tested; is the moving input that approaches it.
- The identity function is continuous everywhere because it does not change distances.
- Constants (Example 5) and the identity function are the two building blocks. Sums, products and quotients of continuous functions are continuous (Theorem 1, Section 5.2.1), so every polynomial is continuous (Example 14).
Every fact used, and where it comes from
| Fact | Used in | Source |
|---|---|---|
| Identity function: | Steps 1–3 | Definition (Basics: functions) |
| Step 2 | Arithmetic | |
| Meaning of a limit; | Steps 2, 3 | Limits, Class XI (Limits and Derivatives) (Basics: what a limit is) |
| Continuous at iff LHL = RHL = | Step 4 | Definition 1, Section 5.2 (Lesson: continuity at a point) |
| Continuous function | Step 4 | Definition 2, Section 5.2 |
| Sums and products of continuous functions are continuous | Take-away 2 | Theorem 1, Section 5.2.1 (Lesson: algebra of continuous functions) |
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