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Chapter 10 · Vector Algebra

Exercise 10.1 · Q3: Scalar or vector: time period, distance, force, velocity, work done

Exercise 10.1Scalars and vectors · Sections 10.1 and 10.2
The question

Classify the following as scalar and vector quantities.

(i) time period    (ii) distance    (iii) force

(iv) velocity    (v) work done

Exam answer

(i) A time period has only magnitude (a number of seconds): scalar.

(ii) Distance is the length of the path travelled, only magnitude: scalar.

(iii) A force acts in a definite direction and has magnitude: vector.

(iv) Velocity is speed in a definite direction, so it has magnitude and direction: vector.

(v) Work done has only magnitude (a number of joules): scalar.

Want the reason behind every step, the basics and the checks?

The one idea this problem is built on

A quantity that involves only one value, its magnitude, is a scalar; a quantity that has magnitude as well as direction is a vector (Section 10.1 and Definition 1). Two pairs here are easy to mix up: distance (how far along the path, a scalar) against displacement (from start to finish, a vector), and speed (a scalar) against velocity (a vector). Work done is a scalar even though it is made from a force and a displacement.

Given, to find, and the plan
Given
Five quantities: time period, distance, force, velocity, work done.
To find
Whether each is a scalar or a vector quantity.
Plan
For each, ask whether a direction is part of the quantity itself. Where a scalar has a vector "twin" (distance and displacement, speed and velocity), compare the two.

Basics you need

1Scalars and vectors

Scalar: one value only, the magnitude, a real number. Vector: magnitude and direction. Section 10.1 lists time, distance, speed and work among the scalars, and displacement, velocity, acceleration and force among the vectors. Basics: some answers need a "which way"

2Distance and displacement

Distance is the total length of the path travelled. Displacement is the directed line segment from the starting point to the finishing point. Lesson: a vector is a length with a direction

3Work done by a force

A constant force F⃗\vec F moving its point of application through a displacement d⃗\vec d does work W=∣F⃗∣ ∣d⃗∣cos⁡θW = |\vec F|\,|\vec d|\cos\theta⁠, where θ\theta is the angle between them. It has the form of the scalar (dot) product of Section 10.6.1. Lesson: only the part of the push along the path does work

Part (i): time period

  1. Decide and classify

    A time period is the time taken for one complete cycle of a repeating motion, for example a pendulum that takes 2 seconds to swing there and back. "2 seconds" says everything; time does not point in any direction in space.

    So time period is a scalar.

    A time period is a length of time, and time is in the book's list of scalars. Example 2 (i) classes "5 seconds" as Time, a scalar, for the same reason.
    Time is a scalar quantity (Section 10.1; Example 2 (i)). Basics: some answers need a "which way"

Part (ii): distance

  1. Compare distance with displacement

    Walk 3 m east from A to B, then 4 m north from B to C. The distance travelled is the length of the path, 3+4=73 + 4 = 7 m. The displacement is the single arrow AC→\overrightarrow{AC}⁠, of length 5 m, pointing from A to C.

    3 m east 4 m north 5 m A C B distance walked = 3 + 4 = 7 m (a scalar: just a number) displacement = 5 m from A to C (a vector: length and direction)
    Drawn to scale (40 px per metre). The path A to B to C (gold) has length 7 m: that is the distance, a single number. The arrow AC→\overrightarrow{AC} (blue) is the displacement: 5 m in a definite direction.
    The distance only adds up lengths, and lengths are numbers; no direction survives in "7 m". The displacement needs a direction to say where you ended up. The same trip gives two different quantities, one of each kind.
    The length of AC→\overrightarrow{AC} is found by Pythagoras: 32+42=5\sqrt{3^2 + 4^2} = 5⁠. Basics: use Pythagoras
  2. Classify

    Distance has magnitude only: distance is a scalar.

    Distance is one of the scalar quantities listed in Section 10.1, while displacement is listed among the vectors. The question asks about distance, so the answer is scalar.
    Distance is a scalar quantity; displacement is a vector quantity (Section 10.1). Basics: some answers need a "which way"

Part (iii): force

  1. Decide and classify

    A force is a push or a pull, and it always acts in some direction. A push of 10 newton to the left and a push of 10 newton to the right have the same size but opposite effects: together they cancel.

    So force is a vector.

    The book's opening example is a football pass: the force involves muscular strength (magnitude) and the direction in which the other player stands. Both are needed to describe the force.
    Force is a vector quantity (Section 10.1; Example 2 (iii): "10 Newton" is Force, a vector). Lesson: a vector is a length with a direction

Part (iv): velocity

  1. Compare velocity with speed

    Speed says how fast, for example 30 km/hr. Velocity says how fast and which way, for example 20 m/s towards north. Two cars at 60 km/hr on the same road, one going north and one going south, have the same speed but different velocities.

    Velocity is the rate of change of displacement, and displacement has a direction, so velocity inherits it. Speed is the rate of change of distance, a scalar, so speed is a scalar.
    Example 2 (iv) and (vi): "30 km/hr" is Speed, a scalar; "20 m/s towards north" is Velocity, a vector. Lesson: Examples 1–3
  2. Classify

    Velocity has magnitude (the speed) and direction: velocity is a vector.

    Velocity is in the list of vector quantities in Section 10.1. Its magnitude is the speed, which is why speed alone is a scalar.
    A quantity that has magnitude as well as direction is a vector (Definition 1, Section 10.2). Basics: some answers need a "which way"

Part (v): work done

  1. See what work done is made of

    When a constant force F⃗\vec F moves an object through a displacement d⃗\vec d⁠, the work done is

    W=∣F⃗∣ ∣d⃗∣cos⁡θ,W = |\vec F|\,|\vec d|\cos\theta,

    where θ\theta is the angle between F⃗\vec F and d⃗\vec d⁠. For example, a 10 N pull at 60° to a 5 m path does work 10×5×cos⁡60∘=2510 \times 5 \times \cos 60^\circ = 25 joules.

    Force and displacement are both vectors, but the work is the product of two magnitudes and a cosine, all real numbers, so the result is a real number. Only the part of the force along the path, ∣F⃗∣cos⁡θ|\vec F|\cos\theta⁠, does work.
    This has the form of the scalar (or dot) product F⃗⋅d⃗\vec F\cdot\vec d defined in Section 10.6.1 (Definition 2), whose value is a real number. Lesson: the dot product
  2. Classify

    "25 joules" says everything about the work; it has no direction. So work done is a scalar.

    Work is in the book's list of scalar quantities (Section 10.1). Energy put into an object does not point anywhere: lifting a box or pushing it along a floor can both use 25 joules.
    Work is a scalar quantity (Section 10.1). Basics: some answers need a "which way"
Result

(i) time period: scalar. (ii) distance: scalar. (iii) force: vector. (iv) velocity: vector. (v) work done: scalar.

(Textbook answer: (i) scalar (ii) scalar (iii) vector (iv) vector (v) scalar.)

Check it with numbers

For the walk in Part (ii): distance 3+4=73 + 4 = 7 m, displacement 32+42=5\sqrt{3^2 + 4^2} = 5 m in the direction tan⁡−143≈53.13∘\tan^{-1}\frac43 \approx 53.13^\circ north of east. The distance needs one number; the displacement needs two (a length and an angle).

For the work in Part (v): cos⁡60∘=0.5\cos 60^\circ = 0.5⁠, so W=10×5×0.5=25W = 10 \times 5 \times 0.5 = 25 J. Turning the pull to 0° (along the path) gives 10×5=5010 \times 5 = 50 J; at 90° it gives 00 J. Each answer is a single number.

Common mistakes
  1. Treating distance as displacement. Distance is the length of the path (a scalar); displacement is the arrow from start to finish (a vector).
  2. Treating velocity as speed. Speed is a scalar; velocity is speed with a direction, a vector.
  3. Calling work a vector because force and displacement are vectors. Work is their scalar (dot) product, a number.
What to take away
  1. Scalars: time, distance, speed, work, mass. Vectors: displacement, velocity, acceleration, force.
  2. Several scalars have vector partners: distance and displacement, speed and velocity.
  3. Combining two vectors can give a scalar: work done is F⃗⋅d⃗\vec F\cdot\vec d⁠.

Every fact used, and where it comes from

FactUsed inSource
Scalar and vector quantities, with the lists of examplesParts (i) to (v)Section 10.1 (Basics: some answers need a "which way")
A quantity with magnitude and direction is a vectorPart (iv)Definition 1, Section 10.2
5 seconds: scalar; 10 Newton: vector; 30 km/hr: scalar; 20 m/s towards north: vectorParts (i), (iii), (iv)Example 2, Section 10.3 (Lesson: Examples 1–3)
32+42=5\sqrt{3^2 + 4^2} = 5Part (ii)Pythagoras theorem (Basics: Pythagoras)
Work done =∣F⃗∣ ∣d⃗∣cos⁡θ= |\vec F|\,|\vec d|\cos\thetaPart (v)Physics (work by a constant force); the same form as the scalar product, Definition 2, Section 10.6.1 (Lesson: the dot product)
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